3v^2=80+8v

Solution for 3v^2=80+8v equation:

3v^2=80+8v

We move all terms to the left:

3v^2-(80+8v)=0

We add all the numbers together, and all the variables

3v^2-(8v+80)=0

We get rid of parentheses

3v^2-8v-80=0

a = 3; b = -8; c = -80;
Δ = b2-4ac
Δ = -82-4·3·(-80)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-32}{2*3}=\frac{-24}{6}
=-4
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+32}{2*3}=\frac{40}{6}
=6+2/3
$